Finding the Distance to Supernova A

Questions

34. Fit the model light curve to your data. Then, move the dotted line to the peak of your light curve to determine the peak apparent magnitude. (Data from Zwicky Transient Facility)
    

    Interactive Light Curve Plot

    Supernova A

    Apparent Magnitude (m)

    Days

    Curve Width

    -2

    Vertical (y) Offset

    -2

    Mean distance from observations is NaN, your peak is below the brightest measurement of

    Reset
35. Enter the value for your 𝚫m15 to calculate the peak absolute magnitude of Supernova A.
    $$\mathrm{\Delta }{m}_{15}=$$

    $$M=-23.60+6.46\left(\mathrm{\Delta }{m}_{15}\right)$$

    Peak absolute magnitude
36. Enter the peak apparent magnitude (m) and absolute magnitude (M) for supernova A into the calculator to find its distance from Earth. (Don’t forget to include the negative sign for M.)
    $$m=$$

    $$M=$$

    $$d=\left(3.26\right){10}^{\frac{m-M}{5}}+1$$

    calculators.output.distanceModulus
37. Record the values for 𝚫m15, peak apparent magnitude (m), peak absolute magnitude (M), and distance of supernova A in the table below.

    Supernova	$$\mathrm{\Delta }{m}_{15}$$	Peak Apparent Magnitude (m)	Peak Absolute Magnitude (M)	Distance (Mly)
    Supernova A